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-5x^2-5x+10x=-2
We move all terms to the left:
-5x^2-5x+10x-(-2)=0
We add all the numbers together, and all the variables
-5x^2+5x+2=0
a = -5; b = 5; c = +2;
Δ = b2-4ac
Δ = 52-4·(-5)·2
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{65}}{2*-5}=\frac{-5-\sqrt{65}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{65}}{2*-5}=\frac{-5+\sqrt{65}}{-10} $
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